Leetcode题解之 —— 二叉树的层次遍历 II
思路
BFS算法
queue
队列辅助
- 内部循环分组
result
反转
题解
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var levelOrderBottom = function (root) { if (!root) { return []; }
const [result, queue] = [[], [root]];
while (queue.length) { const [group, queueLen] = [[], queue.length]; let count = 0;
while (count < queueLen) { const currentNode = queue.shift(); group.push(currentNode.val); currentNode.left && (queue.push(currentNode.left)); currentNode.right && (queue.push(currentNode.right)); count++; }
result.push(group); }
return result.reverse(); }
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